สอบถามการแปลงคำสั่งจากโปรแกรม Visual studio 2010 ไปใช้กับโปรเเกรม code block

มีคำสั่งจากโปรเเกรมVisual studio 2010 มา

อยากทราบว่า ถ้าต้องการเเปลงคำสั่งเพื่อใช้กับโปรเเกรม code block ต้องแปลงยังไง??คะ

คำสั่งประมาณนี้คะ--------------------------------------------------------------------------------



#include "stdafx.h"
#include <stdlib.h>
#include <stdio.h>
#include <math.h>
#include <conio.h>

int _tmain(int argc, _TCHAR* argv[])
{
    
    float c[3],cc[10][3],mu[3],fc[3],m[3],kd[3],Ys[3],Yp[3],a[3],cin[3];
    float Xc[100][3],Xt[100];
    float t,nint,h,tmax,phyP,phyS,phyD,kp,ksi,mum,ks,fout,fin,pi;
    int i,j,k,n;
    char ch;

        printf("\n\n\n\n\n\t\t\tBatch Fermentation simulation program\n");
        printf("\t\t***********************************************");
        printf("\n\n\n");
        printf("\t\t\t\tEnter to continue");
        scanf_s("%c",&ch);
        system("cls");
    
    printf("Enter only values of constants to be used\n");
    printf("Enter 0 for canstant not applicable\n\n");

    printf("initial biomass concentration(c(0)) =");
    scanf_s("%f",&c[0]);
    cin[0]=c[0];
    
    printf("initial substrate concentration(c(1)) =");
    scanf_s("%f",&c[1]);
    cin[1]=c[1];
    
    printf("initial substrate concentration(c(2)) = 0\n");
    c[2]=0;
    cin[2] = c[2];
    
    printf("maximum specific growth rate(mum)=");
    scanf_s("%f",&mum);
    printf("saturation growth constant(ks)=");
    scanf_s("%f",&ks);
    printf("product inhibition(kp)=");
    scanf_s("%f",&kp);
    printf("substrate inhibition(ksi)=");
    scanf_s("%f",&ksi);
    printf("maintenance coefficient(m)=");
    scanf_s("%f",&m[1]);
    m[2]=m[1];
    m[0]=0;
    printf("specific cell death rate(kd)=");
    scanf_s("%f",&kd[0]);
    kd[2]=-kd[0];
    kd[1]=0;
    printf("yield coefficient for biomass on substrate(Yx)=");
    scanf_s("%f",&Ys[1]);
    Ys[0]=1;
    Ys[2]=1;
    printf("yield coefficient for product on substrate(Yp)=");
    scanf_s("%f",&Yp[2]);
    Yp[0]=1;
    Yp[1]=1;;
    
    printf("flow rate in(fin)=");
    scanf_s("%f",&fin);  
    
    printf("flow rate out(fout)=");
    scanf_s("%f",&fout);
    
    printf("total fermentation time(tmax)=");
    scanf_s("%f",&tmax);
    
    printf("percent of product inhibition(pi)=");
    scanf_s("%f",&pi);
    
    a[0]=1;
    a[1]=-1;
    a[2]=1;

    system("cls");

    nint=tmax/10;
    h=nint/10;

    k=0;
    n=0;
    t=0;

    for(int x=0;x<10;x++){
        t+=nint;
        for(j=0;j<10;j++){
            phyP = 1/(1+(c[2]/kp));
            
            if(ksi==0){
                phyS = 1;
            }else{
                phyS = ksi/(ksi+c[1]);
            }
            
            phyD = 1;
            
            for(i=0;i<3;i++){
                mu=((((mum*c[1]*phyP*phyD*phyS)/(ks+c[1]))-kd)*(Yp/Ys)+m)*a;
                fc=(mu*c[0])+(fin*cin)-(fout*c);
                c=c+(h*fc);
                cc[k]=c;//keep history of concentration for only big step
                Xc[n]=c;//keep history of concentration for all step
            }
            Xt[n]=t;//keep history of time
            n = n+1;
        }

        printf("flow rate in(fin)=%f\n",fin);
        printf("k=%d\n",k+1);
        printf("t=%.2f\n",t);
        
        printf("biomass concentration(c(0))=%.2f\nsubstrate concentration(c(1))=%.2f\nproduct concentration(c(2))=%.2f\n\n",cc[k][0],cc[k][1],cc[k][2]);
        k=k+1;
    }
    
    printf("n\tk\tt\tc(0)\tc(1)\tc(2)\n");
    n=0;
    for(i=0;i<k;i++)
    {
        for(j=0;j<10;j++)
        {
            printf("%d\t%d\t%.2f\t%.2f\t%.2f\t%.2f\n",n+1,i+1,Xt[n],Xc[n][0],Xc[n][1],Xc[n][2]);    
            n++;
        }
    }
    

    printf("\n\n enter to exit");
    scanf_s("%d",&n);    

    
    return 0;
}